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If y is given as a function of a parameter t, and x is given as a function of the same parameter t, then \displaystyle \frac{dy}{dx} can be found by using: \displaystyle \frac{dy}{dx} = \frac{\frac{dy}{dt} }{\frac{dx}{dt} } = \frac{dy}{dt} \times \frac{dt}{dx} You can get a better display of the maths by downloading special TeX fonts from jsMath. In the meantime, we will do the best we can with the fonts you have, but it may not be pretty and some equations may not be rendered correctly.

## Glossary

### function

A rule that connects one value in one set with one and only one value in another set.

### parameter

a) a constant or variable term in a function that determines the specific form of the function but not its general nature, as a in f(x) = ax, where a determines only the slope of the line described by f(x).
b) one of the independent variables in a set of parametric equations.

### union

The union of two sets A and B is the set containing all the elements of A and B.

Full Glossary List

## This question appears in the following syllabi:

SyllabusModuleSectionTopicExam Year
AP Calculus BC (USA)3DifferentiationParametric differentiation-
AQA A-Level (UK - Pre-2017)C4DifferentiationParametric differentiation-
CCEA A-Level (NI)C4DifferentiationParametric differentiation-
Edexcel A-Level (UK - Pre-2017)C4DifferentiationParametric differentiation-
OCR A-Level (UK - Pre-2017)C4DifferentiationParametric differentiation-
OCR-MEI A-Level (UK - Pre-2017)C4DifferentiationParametric differentiation-
WJEC A-Level (Wales)C4DifferentiationParametric differentiation-
Methods (UK)M8DifferentiationParametric differentiation-
CIE A-Level (UK)P2DifferentiationParametric differentiation-
Pre-U A-Level (UK)4DifferentiationParametric differentiation-